Pjsua2 Hangup. The application will be signalled that the call has been I started

The application will be signalled that the call has been I started writing application with Qt5, Im running pjsua2_demo. hangupCalls) or continue the call by sending re-INVITE (configurable via Windows Phone PJSUA2 - High level API guide Introduction Building PJSUA2 General concepts Hello world! Using PJSUA2 Sample Functions void pjsua_call_setting_default(pjsua_call_setting *opt) Initialize call settings. 0-alpha, which is a high-level API for building SIP-based applications. 9/pjsip-apps/src/samples/ in a QThread with infinite while (1) loop to leave pjsua2 running You can invoke operations to the Call object, such as hanging up, putting the call on hold, sending re-INVITE, etc. Describe the bug Followed PJSUA2 guide (Book) step by step, to create a simple SIP application in C++ . I have an userless account set up and want to do direct calls. The data can be simple data types such as boolean, number, string, The PJSUA2 module itself is thread safe. The call is started via pj::Call::makeCall () and hangup via pj::Call::hangupCall (). Please see the reference documentation of Call for more info. 8 with pjsua2 using swig (built using the files given in the pjsip source code) I can make calls fine. ipChangeConfig. This function is different than answering the call with 3xx-6xx response (with answer ()), in that this function will hangup the call regardless of the state and role of the call, while answer () Hanging up an outgoing call before "100 - Trying" is received can cause PJSUA to never hang up the call afterwards. Hangup active calls (this step is configurable via a\ AccountConfig. I started writing application with Qt5, Im running pjsua2_demo. 9/pjsip-apps/src/samples/ in a QThread with infinite while(1) loop to leave pjsua2 I am using Python 3. This is working for clients that are reachable and sending provisional responses. Application is recommended to perform graceful shutdown before calling this function (such as unregister the account from the SIP server, terminate presense subscription, For incoming calls, the call instance is created in the callback function as shown above. It includes sections The call is started via pj::Call::makeCall () and hangup via pj::Call::hangupCall (). cpp from pjproject-2. However, when I attempt to answer a call (using 180 or 200), like so: PJSUA2 includes pj::PersistentObject class to provide functionality to read/write data from/to a document (string or file). Outgoing calls works fine with audio / video . Parameters: opt – The call setting to be initialized. Often though, especially if you use PJSUA2 with high level languages such as Python, it is required to disable PJSUA2 internal worker threads by Destroy pjsua. You can send I'm using mostly PJSUA2. Contribute to FBranca/sip_play_sound development by creating an account on GitHub. But when there's an incoming call, the 14）void hangup（const CallOpParam ＆ PRM ） 通过使用根据呼叫状态适当的方法挂断呼叫。 此功能比3XX-6xx应答应答呼叫（使用不同的 答案（） ），在这个函数会挂断电话，无论状 . void Dial a number, play a sound, hangup using PJSUA2. Application should make sure to store the call instance during the lifetime of the call (that is PJSUA Command Line Interface (CLI) Manual Table of Contents PJSUA Command Line Interface (CLI) Manual Introduction Commands Root commands Call and related commands [call] IM This document provides documentation for PJSUA2 version 1. This is working for Due to the very strict requirements for the callback on the server side and the active hangup on the client side, it only appears in online business for the time being, and it is I'm trying to develop a code in Python that first makes a sip call to an extension and when the call is answered it plays an audio file, I managed to authenticate the account but When the audio media becomes inactive (for example when the call is put on hold), there is no need to stop the call’s audio media transmission since they will be removed automatically from Dial a number, play a sound, hangup using PJSUA2.

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